We want to compute the limit below with the I'Hospital's Rule if it applies. lim 1 - sin(9x) C->7/2 cos (3x) a) What is the indeterminate type of the limit? 0/0 0 00/00 b) According to I'Hospital's Rule, 1 - sin(9z) A(a) lim = lim cos (3x) C+7/2 B(a) where [A(z), B(x)] = FORMATTING: Enter your answer as [A(x), B()], including the square brackets and with a comma (,) between the terms. For this question, you must use strict scientific calculator notation: multiplication is written * ; for example, you must write 2x as 2*x. c) Conclude that 1 - sin(9x) A(x) lim lim X-+7/2 cos(3x) C-+1/2 B(x)