webassign.net A random sample of 25 wolf litters in Ontario, Canada, gave an average of x = 5.2 wolf pups per litter, with estimated sample standard deviation s wolf litters in Finland gave an average of x2 = 3.4 wolf pups per litter, with sample standard deviation s = 1.4. USE SALT = 1.0. Another random sample of 12 (a) Categorize the problem below according to parameter being estimated, proportion p, mean , difference of means - H2, or difference of proportions P1 - P2. Then solve the problem. OP1 P2 OP (b) Find an 90% confidence interval for - H2, the difference in population mean litter size between Ontario and Finland. (Use 1 decimal place.) lower limit upper limit (c) Examine the confidence interval and explain what it means in the context of this problem. Does the interval consist of numbers that are all positive? all negative? of different signs? At the 90% level of confidence, does it appear that the average litter size of wolf pups in Ontario is greater than the average litter size in Finland? Because the interval contains only positive numbers, we can say that the average litter size of wolf pups is greater in Ontario. Because the interval contains both positive and negative numbers, we can not say that the average litter size of wolf pups is greater in Ontario. We can not make any conclusions using this confidence interval. Because the interval contains only negative numbers, we can say that the average litter size of wolf pups is greater in Finland. Need Help? Read It 2. [-/4 Points] DETAILS BBUNDERSTAT12HS 7.R.004. MY NOTES ASK YOUR TEACHER Anystate Auto Insurance Company took a random sample of 364 insurance claims paid out during a 1-year period. The average claim paid was $1560. Assume = $238. Find a 0.90 confidence interval for the mean claim payment. (Round your answers to two decimal places.) lower limit $ $ upper limit Find a 0.99 confidence interval for the mean claim payment. (Round your answers to two decimal places.) lower limit $ upper limit $ Nood Heln2 Read It