webassign.net/web/Student/Assignment-Responses/last?dep=28320924 Twovu TICIPT Viewing Saved Work Revert to Last Response 0.11 Points] DETAILS SCALCET9 2.3.037. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A graphing calculator is recommended. Use the Squeeze Theorem to show that lim x2 cos(16xx) = 0. Illustrate by graphing the functions f(x) = -x2, g(x) = x2 cos(16xx), and h(x) = x2 on the same screen. Let f(x) = -x2, g(x) = x2 cos(16ntx), and h(x) = x2. Then [? v s cos(16RX) s ? v = [? v s x2 cos(16ntx) s ? v . Since lim f(x) = lim h(x) = by the Squeeze Theorem we have * - 0 x - 0 ' lim g(x) = x -0 Need Help? Read It Watch It