Question
What does it mean when y = 0 for a graph of an algorithm? Like if an algorithm runs in nlog_2(n) steps, what does it
What does it mean when y = 0 for a graph of an algorithm? Like if an algorithm runs in nlog_2(n) steps, what does it mean when n is 1 since 1log_2(1) = 0? Does that mean it runs in 0 steps when n = 1 and is infinitely efficient? Or does that just mean constant time? I'm very confused.
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Advanced Database Systems
Authors: Carlo Zaniolo, Stefano Ceri, Christos Faloutsos, Richard T. Snodgrass, V.S. Subrahmanian, Roberto Zicari
1st Edition
155860443X, 978-1558604438
