What if she had played 20 games and won 18? Would that provide stronger, weaker, or evidence of similar strength compared to 12 wins out of 20, to conclude that her long-run proportion of winning at Minesweeper is higher than 0.50? Explain how you are deciding.

Weaker because the statistic (18/20 = 0.90) is much farther away from the null hypothesized value (0.50) than before (12/20 = 0.60).

Stronger because the statistic (18/20 = 0.90) is is much closer to the null hypothesized value (0.50) than before (12/20 = 0.60).

Weaker because the statistic (18/20 = 0.90) is much closer to the null hypothesized value (0.50) than before (12/20 = 0.60).

Stronger because the statistic(18/20 = 0.90) is much farther away from the null hypothesized value (0.50) than before (12/20 = 0.60).