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What if the isothermal process was performed irreversibly by suddenly reducing the pressure above the piston from its initial value P1 = nRT/V, to its

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What if the isothermal process was performed irreversibly by suddenly reducing the pressure above the piston from its initial value P1 = nRT/V, to its final value P2 = nRT/V2? Show that the work done on the gas is now Wirrev = -nRT 1 > Wrev on N Hint: use In(1/x) > 1 - x

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