What is f(0.99), f(1.01) and the coordinates of point A?

Suppose that the only information we have about a function f is that f(1) = 4 and the graph of its derivative is as shown. y = f'(x) (a) Use a linear approximation to estimate f(0.99) and f(1.01). f(0.99) = 4.01 x f(1.01) = 3.99 X 2. (5 points) Consider the curve x3 + y' = 3xy. (a) (3 points) Find an expression for dy dx (b) (2 points) Find the coordinates of the point A (where the tangent line is horizontal)