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What is the appropriate conclusion in the context of this problem? 0 With 5% significance level, | reject the alternative hypothesis. Based on the data,

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What is the appropriate conclusion in the context of this problem? 0 With 5% significance level, | reject the alternative hypothesis. Based on the data, we can say that ten-year risk of coronary heart disease and stroke are not associated. C) With 5% significance level, I fail to reject the null hypothesis. Based on the data, we can say that ten-year risk of coronary heart disease and smoking stroke are not associated. 0 With 5% significance level, I accept the alternative hypothesis. Based on the data, we can say that ten-year risk of coronary heart disease and stroke are not associated. C) With 5% significance level, I cannot reject, nor fail to reject, either hypothesis based on the p-value. 0 With 5% significance level, | reject the null hypothesis. Based on the data, we can say that ten-year risk of coronary heart disease and stroke are associated. Question 5 (2 points) In April 2018, a cardiovascular study was carried out in the city of Framingham, Massachusetts(Source: https://www.kaggle.com/amanajmera1/framingham-heart- study-dataset/data). This long-term study collected data on 16 risk factors and ten- year risk of coronary heart disease. The nature of the risk factors presents an opportunity to employ the Chi square independence test to test the hypothesis of the association between the Ten-Year Risk of Coronary Heart Disease (TRCHD) and some risk factors. One of the risk factors measured is whether a participant had suffered stroke, participants respond "Yes" if they have had stroke and "No" if not. Please refer to the table below in answering the following questions. Disease Outcome Stroke (No) Stroke (Yes) Total TRCHD(No) 3086 13 3099 TRCHD(Yes) 549 8 557 Total 3635 21 3656 What is the appropriate conclusion in the context of this problem?What are the appropriate null and alternative hypotheses for the Chi-Square test? Hint: What would you expect fora frequency if there was no difference in prevalence among the age groups below. 0 H0; P1 = 0125,132 = 0125,133 = 0.125,}?4 = 0.125,?5 = 0.125, P6 = 0125,137 = 0.125, P; = 0.125 HA : At least one proportion differs from what is expected. 0 H0: P1 = 0.10 .132 = 0.20133 2 0.30.134 = 0.40, P5 = 0.50 P6 = 0.60.P7 = 0.70.138 = 0.80 HA : At least one proportion differs from what is expected. OHO:P1 8.P2 24,133 30,134 27,135 19,1)6 20,107 14,138 23 HA : At least one proportion differs from what is expected. O Ho: P1 0.59, P2 0.15, P3 018, P4 0.16, P5 0.125,},6 = 0.125,?7 = 0.125, P8 = 0.125 HA: At least one proportion differs from what is expected. 0 Ho: At least one proportion is the same as expected. HA: All the proportions are different from expected. People of all age groups can be infected by COVlD-19. Data were collected from laboratory confirmed COVlD-19 cases in Kalamazoo County (as of 3:00 PM April 19, 2020) and are presented below. We are interested in testing (at 5% level of significance) whether the percentage of at least one age group differs significantly from the others. Age Group Cases 0-19 8 20-29 24 30-39 30 40-49 27 50-59 19 60-69 20 70-79 14 >79 23 Total 165

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