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What is the center of the shape formed by the (x-3)2 (y+5)2 equation - = 1? 49 25 (0, 0) (-3, 5) (3,-5) (9,25)
What is the center of the shape formed by the (x-3)2 (y+5)2 equation - = 1? 49 25 (0, 0) (-3, 5) (3,-5) (9,25) (-9, -25)
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Precalculus Concepts Through Functions A Unit Circle Approach To Trigonometry
Authors: Michael Sullivan
5th Edition
0137945139, 9780137945139
