what is the conclusion? is it: we reject Ho. There is significant evidence to suggest the mean is not 9.8% or is it number 2. We keep the Ho. There is no evidence to suggest the mean is significantly different than 9.8%

In 2003, 9.8% of NASA job applicants who were tested for Top Secret Clearance failed the test. At the 0.10 level of significance test the claim that the failure rate is now lower if a random sample of 1230 current job applicants results in 150 failures. (A proportion) a) Hypothesis: HO: __p=.098__The proportion is 0.098 (9.8%) H1: _ p=/.098_The proportion is significantly lower or higher than 0.098 (9.8%) Alpha = .10 p-hat = 150/1230 = .1219 p = .098 (previously known proportion) q = 1-.098 = .902 n = 1230 critical value z = 1.645 test statistic z = 2.819