What is the correct form of the partial fraction decomposition for the following integral? 5(24 + 5) (2 - 6) (22 - 1)2(x2 +6)2" dx OA. A B C x - 6 + D + E Fx + G a + 1 ( ac + 1) 2 + + Ha +I x - (ac - 1)2 + x2 + 6 (202 + 6)2 dx O B. There is no partial fraction decomposition because the denominator does not factor. O C. There is no partial fraction decomposition yet because there is cancellation. O D. There is no partial fraction decomposition yet because long division must be done first. OE./ A B C D + E 6 x+1 (ac + 1) 2 + + FatG x - (ac - 1)2 + 2 2+ 6 dx OF. A B C - 6 + (ac2 - 1) 2 + (2 2 + 6)2 dx OG . A Bx + C Dx + E x - 6 + (202 - 1) 2 (202 + 6) 2 dx OH. A ac - + Bx+C Cx+D 6 Ex+F Gx+ H 2 2 - 1 (202 - 1) 2 + 2 2 + 6 (202 + 6) 2 dx