Question: Using lab 7 with a three-day lead time (all original values), we will analyze six different scenarios to determine which would be the best scenario

Using lab 7 with a three-day lead time (all original values), we will analyze six different scenarios to determine which would be the best scenario based on the total cost.

Scenario A - Min is 3,500 and Max is 5,500. All other values remain the same as lab 7 original values. The total cost would be blank .

Scenario B - Min is 3,500 and Max is 6,000. All other values remain the same as lab 7 original values. The total cost would be blank .

Scenario C - Min is 4,000 and Max is 5,500. All other values remain the same as lab 7 original values. The total cost would be blank .

Scenario D - Min is 4,000 and Max is 6,000. All other values remain the same as lab 7 original values. The total cost would be blank .

Scenario E - Min is 4,500 and Max is 5,500. All other values remain the same as lab 7 original values. The total cost would be blank .

Scenario F - Min is 4,500 and Max is 6,000. All other values remain the same as lab 7 original values. The total cost would be blank .

Choose from: $259,530 or $290,521 or $246,492 or $301,993 or $307,893 or $424,627

Based on the above scenarios, we know that scenario blank would cost us the most, therefore we wouldn't want to use those min and max values. On the flip side, scenario blank yields us the best combination of min and max resulting in the least cost.

Scenario: E or C or A or D or F or B

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