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What is the maximum mass of NO2 that is formed when 7.5 g N205 are consumed ? [Molar mass N205 is 108.0 g/mol] 2N205(9) -->

What is the maximum mass of NO2 that is formed when 7.5 g N205 are consumed ? [Molar mass N205 is 108.0 g/mol] 2N205(9) --> 4NO2(g) + O2(g) [Molar mass NO2 is 46.0 g/mol) 

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To solve this problem first calculate the number of moles of N2O5 that are consumed 75 g N2O5 x 1 ... blur-text-image

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