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What is the mistake in the second alert statement in the code? function func 1 ( n ) { if ( n = = 0

What is the mistake in the second alert statement in the code?
function func1(n)
{
if (n==0)
return 0;
else
return (n+func1(n-1);
}
function func2(n, result)
{
if (n==0)
return result;
else
return (n+func2(n-1, n+result));
}
alert ("output of func2(4,0) is "+ func2(4,0));
alert ("output of func1 is "+ func1(4,0)) ;
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