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What is the mistake in the second alert statement in the code? function func 1 ( n ) { if ( n = = 0
What is the mistake in the second alert statement in the code?
function funcn
if
return ;
else
return nfunc;
function funcn result
if
return result;
else
return nfuncn nresult;
alert output of func is func;
alert output of func is func ;
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