What is the output of the following code: re.findall('ab[1,3]cab1,3c ac abbc ab13c abbbbc ab[1,3]c') 1. ['abbc'] 2. ['ab(1,3]c'] 3. ['ab1,3c'] 4. ['ab13c'] 5. ['ab(1,3]c,'ab(1,3}] 6. ['ab(1,3)cab1,3c ac abbc ab13c abbbbc ab(1,3)c'] 7. None of them