1. What is the probability of obtaining a test score above 92 for a distribution with a M = 71 and an SD = 5.50 (try drawing out a normal curve with the values you need to find if you're struggling)? (3pts)

1. First compute the z-score for a score of 92 by completing the transformation equation below:

z = (x - M) / SD

z = 92-71/5.50

z = 3.82

1. Now look in Appendix B of your textbook for the z-score you obtained. You need to figure out the probability of getting above 92. Think about what is to the left of the mean on a standard normal distribution for help.

Area b/t the mean and the z-score =

Area to the right of the mean total =

Probability of obtaining an 92 or above =