What is the rate constant for a reaction in which the free energy of activation $(G^{})$ equals $94\mathrm{.}1k\frac{J}{m}ol$ at $25C?$

$1\mathrm{.}3{10}^{-4}{s}^{-1}$

$9\mathrm{.}7{10}^{-5}{s}^{-1}$

$2\mathrm{.}0{10}^{-4}{s}^{-1}$

$3\mathrm{.}3{10}^{-4}{s}^{-1}$

$2\mathrm{.}9{10}^{-4}{s}^{-1}$

$1\mathrm{.}7{10}^{-4}{s}^{-1}$