What is the slope of the tangent line to the curve y=J(x-2] at the point (6,2)? 0 (E) None of the choices 0 14 O 4 O 1/2 02 Find dy/dx, given the following: y = (x'+2x) V2x-4 O (x3+2x ) 2 + 3 (3x2 + 2 ) (x3 + 2 x) 2 V (2x-4) V (2x-4)3 O (x3+ 2 x) 2 17x3-36x2+10x-24 V2x-4 2x-4 O (E) None of the choices O V (x3+ 2x ) 2 = 3(3x2 +2) (x3+2x) + (2x-4)3 V2x-4 O (x3+ 2x ) = 17x3-36x2+10x-24 V(2x-4) (2x-4)2