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What is the smallest number of whole logs ( = 725 kg/m 3 , radius = 0.0890 m, length = 2.70 m) that can be

What is the smallest number of whole logs ( = 725 kg/m3, radius = 0.0890 m, length = 2.70 m) that can be used to build a raft that will carry four people, each of whom has a mass of 88.0 kg?

HINT:

The buoyant force on the logs must be at least equal to the weight of the logs plus the weight of the people: FB=WL+WPFB=WL+WP. Assume there are NN logs and they are submerged just below the surface. The total buoyant force is equal to FB=NgVFB=NgV. The total weight of the logs is equal to NN times the weight of a single log. Make these substitutions and solve for NN. NN may not be a whole number, so round to the appropriate whole number.

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