Question
What is the solution to the following system? 4+=3 28+4=9 520+7=19 Let s and t be dummy variables such that s and t go from
What is the solution to the following system?
4+=3
28+4=9
520+7=19
Let s and t be dummy variables such that s and t go from 0 to positive infinity. The solution set is (4s + t + 4, s, 2t + 1, t).
Let s and t be dummy variables such that s and t go from negative to positive to infinity. The solution set is (4s + t + 4, s, 2t + 1, t).
Let s and t be dummy variables such that s and t go from 0 to 234. The solution set is (4s + t + 4, s, 2t + 1, t).
This system of linear equations has no solution.
Let s and t be dummy variables such that s and t go from negative infinity to 0. The solution set is (4s + t + 4, s, 2t + 1, t).
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