What magnetic field BB is needed to keep $996-$GeVGeV protons revolving in a circle of radius $1\mathrm{.}6$ kmkm $?$ Use the relativistic mass. The proton's "rest mass" is $0\mathrm{.}938$ GeV$/$c$2$GeV$/$c$2.(1$ GeVGeV $=109$eV$109$eV$)[$Hint: In relativity, mrelv$2/$rmrelv$2/$r $=$ qvBqvB in still valid in a magnetic field, mrelmrel $=$ mm$.]$