What proportion of OSU students eat breakfast on a regular basis? To help you estimate this unknown population proportion, you survey a random sample of 380 OSU students, and 159 of these students tell you that they eat breakfast on a regular basis. 1. From the information given above, what is the sample proportion? Please compute that value below and round your answer to three decimal places

5. Return to the sample proportion you computed to answer Question 1. Use that proportion and what you know about the sample size to construct a 95% confidence interval. Round the lower and upper bounds to three decimal places each. Lower bound: Upper bound:

4 6. Without performing any calculations, explain how the confidence interval you constructed above would have been different if the level of confidence had been 99% instead of 95%. 7. Suppose the proportion of all OSU students who regularly eat breakfast is actually 0.435. Is this value of 0.435 included in your 95% confidence interval? In other words, does 0.435 fall somewhere between the lower and upper bounds that you calculated above, to answer Question 5? 8. Your classmate, Kit, also surveys a random sample of n = 380 OSU students, and he finds the proportion in his sample who say they regularly eat breakfast is 0.366. When Kit constructs a 95% confidence interval, his interval ends up being from 0.318 to 0.414. The population proportion of 0.435 is not included in this confidence interval. Does this surprise you? Please explain. 9. When asked to put together a confidence statement based on the interval he constructed, Kit writes the following: "I am 95% confident the interval from 0.318 to 0.414 includes the proportion of OSU students in my sample who eat breakfast regularly." Is anything wrong with this confidence statement? Please explain.