What was your average annual rate of return if you invested $$1000$ and you have $$6,000$ at the end

of $12$ years?

Input your answer as a percentage rounded to two decimal places $($i$.$e$.10\mathrm{.}441\%$ would be $10\mathrm{.}44$ ;

$10\mathrm{.}448\%$ would be $10\mathrm{.}45)$