What will be displayed by the following code?

#include

using namespace std;

const int COLUMN$\_$SIZE $=3$;

double sum$($const double m$[][$COLUMN$\_$SIZE$],$ int rowSize$)$

$\{$

int sum $=0$; $//$ Please note sum is declared int here

for $($int i $=0$; i $<$ rowSize; i$++)$

sum $+=$ m$[$i$][$i$]$;

return sum;

$\}$

int main$()$

$\{$

double m$[3][3]=\{\{1,2,3\},\{1\mathrm{.}5,2\mathrm{.}5,3\mathrm{.}5\},\{0\mathrm{.}1,0\mathrm{.}1,0\mathrm{.}1\}\}$;

cout $<<"$

Sum of all elements is$"<<$ sum$($m$,3)<<$ endl;

return $0$;

$\}$

$4\mathrm{.}5$

$4$

$3$

$3\mathrm{.}6$

$3\mathrm{.}0$

Try again.

m$[0][0](2),$ m$[1][1](2\mathrm{.}5),$ and m$[2][2](0\mathrm{.}1)$ are summed. Note that sum is declared int. When you assign a floating$-$point value to an int, the fractional part is truncated.