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What will be the output of the following code snippet: from datetime import datetime as dt datel = 2 3 / 0 9 /

What will be the output of the following code snippet:
from datetime import datetime as dt
datel="23/09/2019"
x=dt. strptime datel, (:?'%d%m3Y''}
09/23/201900:00:00
23/09/2019
2019-09-2300:00:00
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