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What will be the output of the following code snippet: from datetime import datetime as dt datel = ' 2 3 / 0 9 /

What will be the output of the following code snippet:
from datetime import datetime as dt datel='23/09/2019' x=dt.strptime (datel,'%d/%m/%Y')
Answer Choices:
a)23/09/2019
b)09/23/201900:00:00
c)2019-09-2300:00:00
d)2019-09-23

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