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What would be the answer? If y = 3u2 + 2u and u = Vx2 + 5 dy dx would be: (6 VX2 + 5

What would be the answer?

If y = 3u2 + 2u and u = Vx2 + 5 dy dx would be: (6 VX2 + 5 + 2) ( X Vx 2 + 5 0 (3 Vx2 + 5 + 1 ) ( X (x 2+ 5) 0 (6 ( 3412 + 21) + 2) ( X Vx2+5 (3 VX2 + 5 + 1 ) ( 7 x Vx 2+5

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