What's the answers for question b

Shown below is the output from a linear model predicting armspan (in cm) from height ' (in inches) and summary statistics. Assume that the association between armspan and height is linear. Use the output and summary statistics to complete parts a through d. LinReg y=a+ bx Standard 3 = 5011128941 M63" Deviation b = 2.454107389 Height, X 63.14 3.15 r2 = 0898735739 Armspan, y 159.95 18.15 r = 094801674 . ~*--~.C:>--- a. Report the regression equation, using the words "Height" and "Armspan," not x and y. Predicted Height = 2.45 + 5.01 Armspan _ Predicted Armspan = 5.01 + 2.45 Height Predicted Height = 5.01 + 2.45 Armspan Predicted Armspan = 2.45 + 5.01 Height b. Determine the corresponding values and verify the slope by using the formula r= [:l (Round to three decimal places as needed.) 5y = D (Round to two decimal places as needed.) 3x = D (Round to two decimal places as needed.) b = D (Round to two decimal places as needed.)