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When 6:112 1 32:33; 23/4 = 40. dd: _ : I; The slope of the tangent line to this curve at the point (2, 2)
When 6:112 1 32:33; 23/4 = 40. dd: _ : I; The slope of the tangent line to this curve at the point (2, 2) is The equation of the tangent line to this curve at this point is 3/: f. (1 point) Find dy/ da by implicit differentiation. tan(x - y) = y 1 + x2 2xy + sec- (x-y) dy (1+x2 2 = dx sec? ( x - y ) + 1 1 + x 2
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