When current is passed through the sodium sulfate cell, hydrogen and oxygen gas are formed. Calculate the cell potential required for the formation of 0.25 atm of oxygen and 0.50 atm of hydrogen gas. The pH is 10 on the cathode surface and pH 4 on the anode surface. When a current of 0.32 amps flows through the solution, the resistance of the solution is 3 Ω. The overvoltage at the anode is 0.580 V and the overvoltage at the cathode is 0.584 V.

O2 + 4 H+ 4e- ↔ 2 H2O E0 = 1.2291 V

2 H2O + 2e- ↔ H2 + 2 OH- E0 = - 0.8280 V

A. -4.811V

B. -3.2211V

C. -3.6894V

D. -1.0503V