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When I calculate it out I get (x^6/6)-(x^2/2)-1=-4/3 after subbing the 1 for x. though 4/3 is incorrect. tried using 8/3 because there's 2 regions

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When I calculate it out I get (x^6/6)-(x^2/2)-1=-4/3 after subbing the 1 for x. though 4/3 is incorrect. tried using 8/3 because there's 2 regions though also incorrect. Can someone help me?

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Consider the following equations. x} =x5+2 g[x] =x+2 Sketch the region bounded by the graphs of the equations. Find the area of the region. x

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