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When rolling two six-sided dice, what is the probability of rolling a total combination of five, given that one die rolls a one? I believe
When rolling two six-sided dice, what is the probability of rolling a total combination of five, given that one die rolls a one?
I believe this is conditional probability, P(E1|E2). My professor suggested this answer:
P(rolling a combination of 5 and player rolls a one) / P(player rolls a one) = (2/36) / (11/36) = 2/11
I don't understand why the denominator P(player rolls a one) would equal 11/36 and not 1/6.
What is the best way to solve this problem?
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