where did I go wrong in this problem?

3. Two resistors with resistance 200 0 and 500 $2 are connected in parallel to a 20 V power supply. How much will the current through the 500 2 resistor change if you insert a non-ideal ammeter with an internal resistance of 500 0? 5005 20V - 6005 - 20v soon TR 200 Reg = 200 + 500 =007 2 = 142. 86 I = E = 20 10. 02A Rtr 500+500 1000