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Wherever I May Roam A stunt car, initially at rest, is accelerated up a ramp at 5.5m/s'. The ramp is 25 meters long and is

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Wherever I May Roam A stunt car, initially at rest, is accelerated up a ramp at 5.5m/s'. The ramp is 25 meters long and is tilted 30.0. After the car leaves the ramp, it is in free-fall. L=25M TO = 30 1. What is the magnitude and angle of its velocity vector 1.00 seconds after it has left the ramp? 2. How far from the edge of the ramp does the car land? 3. A student is working on part 2, and they write the following lines as part of their solution: Call vo the velocity of the car as it leaves the ramp. Uf,y = vo,y + at 0 = vo,y - gt t = vo,y/9 D = vo,xt D = vo,x X Vo,y/ 9 What physics mistake(s) did they make? How could you explain to them how to avoid making this mistake

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