Which graph represents two functions that are decreasing on all points across the domain that is common to both functions? h(2 ) i(2) 23 4 h ( z) h (= ) j(=) h( 2)Which of the following graphs shows a system of equations with the same end behavior for both functions? 6 -5 4 -3 2 -10 2 5 6 8 9 10 11 12 4 f (t) -6 -8 -10 -12 g (t) -14 -16 -18 -20 -6 -5 -4 -3 -2 -10 23 4 5 8 9 10 11 12 -6 g(t) -8 O -10 -12 f(1) -14 -16 -18 -20-6 -5 4 -3 -2 -10 1 3 4 5 8 9 10 11 12 -2 4 O -10 9(t) 1-12 f(1) -14 -16 -20 -6 -5 4 -3 -2 1 0 1 2 3 4 5 7 9 10 11 12 -2 -4 -6 O -12 g(t) f (1) -14 -16 -10 -20What values does the function f(x) = x+1 - 3 have in its range that are not in the range of the graph of 90:)? The graphs of f {x} = x3 + x2 6x 1 and 9(1) 2 e" 2 have which of the follawing features in common? 404444-34 ' 0 Range ' O xintercept ' O yintercept ' 0 End behavior Michael solved the system of linear equations and provided the solution. 3x - 3y = 6 4x - 7y = 2 Step 1 4(3x - 3y = 6) -3(4x - 7y = 2) Step 2 12x - 12y = 24 -12x + 21y = -6 Step 3 9y = 18 Step 4 y = 2 In which step did Michael show his first error? O Step 2 O Step 3 O Step 4 O No errors are present in the solution Question 2(Multiple Choice Worth 2 points) (02 02 MC) In a game of cornhole, Sasha tossed a bean bag and it landed at the edge of the hole. The hole can be represented by the equation x2 + )? = 5, and the path of the bean bag can be represented by y = 0.5x2 + 1.5x - 4. To which points could she have tossed her bean bag? O (-1, -2) or (-2, 1) O (1, -2) or (2, 1) O (-1, 2) or (-2, -1) O (1, 2) or (2, -1)If a nonlinear system of equations contains one linear function that never touches the quadratic function, then the system has which of the following? O No solution O One solution O Two solutions O Infinitely many solutions Question 4(Multiple Choice Worth 2 points) (02.02 MC) The path of two bumper cars can be represented by the functions 2x + y = -4 and y = x2 - x -6. At which locations will the bumper cars hit one another? O (-1, -4) and (1, -6) O (-2, 0) and (2, -4) O (-2, 0) and (1, -6) O (-1, -4) and (2, -4)