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Why do you time reverse one signal when multiplying against the other, e.g. a(*b(t-t). It may be easiest to answer this question by considering one

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Why do you time reverse one signal when multiplying against the other, e.g. a(*b(t-t). It may be easiest to answer this question by considering one signal to be a signal inputted into a system and the other signal to be the way the system responds to an input(10 pts)

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