with detailed solution formulas given used it handwritten neat and clean

Kinematics Vf = Vo + at 24 : Final velocity Vf = 1702 + 2 ax Vo : Initial Velocity x: distance x = Not + + at 2 a : acceleration X = No + Uf t : time N Rectilinear motion 74 = Not + gt of = VO 2 + 2gg or Vf = VV0 2 + 2gy y = Not + 2g+ 2 Using quadratic equation, t = 16 + Jb2 - 4ac Operations + : if abject going down - : if dict gring upnewtour Can of Gravitation GM, M 2 4 r 2 6 = 6. 67 x 10- " N. m?/ leg? r : distance between the particles canter to center ) F: common gravitational force of attraction 6 ME ME : mans of Earth = 5. 98 x 10 us RF - radius of Earth = 6.38 x 10 m6. Find the travel time of a motorcycle which travelled with an initial velocity of coke and an acceleration of 15me to cover a distance of 10 km. 7. a crate of fruits has a mass of 75 kg. It was pushed down by an inclined force of 5001, directed at an angle of 45 measured from the horizontal plane. The coefficient of kinectic friction between the bottom of the crate and the surface were the crate was allding was 0:25. Determine the acceleration of the crate. 8. a wooden box has a mass of 50 kq and is motionles on a surface whose angle of inclination is 90, and additional mass, no matter how small, that will be placed on Top of the wooden box will cause it to start sliding down the inclined surface. Find the maximum static friction force that prevented the worden box from sliding.\fProjectile motion Vertical component, Vo Horizontal Component, Vo Voy = Vo sine Vox = Vocost R 1 13 1 As Freely Falling Body : As Rectilinear motion : Vfy = Voy + gt Vfy = Vox y = Vogt $ 2 gt ? * = Voxt LO MO Boron 10.81 Vfu 2= Voy2+ 2gy or Vry =Voy? + 2gy uminium 6.982/ onnatione + : Vo is downward um : Vo is upward Germaniu 3 2 72.630 For Displacement of a projectile or ) For Final Valucity of a Panictile Sn Tin r= v x 2 + y 2 118.71 24 = VVox 2 + Voy ? da ead