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With the data below: discuss statistical terms what is tested below, the result you found, and propose why that result might be so Suffolk county
With the data below: discuss statistical terms what is tested below, the result you found, and propose why that result might be so
Suffolk county 2003 | Suffolk county 2018 |
PM2.5 AQI>50 DAYS: 43 | PM2.5 AQI>50 DAYS: 8 |
Sample size: 111 | Sample size: 116 |
# of success: 3.78 | # of success: 6.90% |
Hypothesize | ||||||||
To test whether the proportion of days that do not have "Good" air quality has changed between 2003 and 2018 | ||||||||
p1 : 2018 proportion of successes for population 1 | ||||||||
p2: 2003 proportion of successes for population 2 | ||||||||
Null Hypothesis | H0: p1- p2= 0 | |||||||
Alternative Hypothesis | HA: p1- p2 0 | |||||||
Prepare | ||||||||
Our test statistic is the difference between our sample proportions | ||||||||
The sample satisfies the Random Sample requirement (assumption) | ||||||||
The sample satisfies the Independent Sample requirement as the samples are independent of each other. | ||||||||
The sample satisfies the Independent within Samples requirement as observations within each sample are independent of one another | ||||||||
To prove the large sample requirement, we use the pooled sample proportion | ||||||||
pooled sample proportion | 0.23 | (42 + 8)/(111 + 116) | ||||||
Successes | p1 | 0.00 | 116*.37 | |||||
Successes | p2 | 0.00 | 111*.37 | |||||
Failures | p1 | 89.32 | 116*(1-.23) | |||||
p2 | 85.47 | 111*(1-.23) | ||||||
Interpret | ||||||||
Our p-value (.0001) is less than our significance level (.05), so we reject the null hypothesis. We can therefore conclude that the proportions are different in the two populations. | ||||||||
Hypothesis test results: | ||||||||
Difference | Count1 | Total1 | Count2 | Total2 | Sample Diff. | Std. Err. | Z-Stat | P-value |
p1- p2 | 8 | 116 | 42 | 111 | -0.30941 | 0.055 | -5.623027 | <0.0001 |
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