Without time wasting do question soon

Your measurements of the resistance for each of 4 brass wires should have shown that the resistance was inversely proportional to the cross section area A of the wire, that is that R equals space rho L divided by space A where space A equals space pi D squared space divided by 4 space. If you asked Desmos to fit these data you could get the resistivity, but you can do it equally well from one value. What did you find for the resistivity of brass? Hint: Find the area of the wire in square meters. For 24 cm of wire R is the resistivity multiplied by 0.24 and divided by the area. You can do all this in Desmos with the full list too this way Make a list of diameters in inches with D = [0.020,0.032,0.040, 0.050]. Convert those to meters using 1 inch = 25.4 mm or 0.0254 m. The command is simply D = 0.0254*[0.020,0.032,0.040, 0.050]. Make another list of resistances. It will begin R = [0.0869, ...] with the resistance for the smallest wire. Then find the areas A = pi *D*D/4. Desmos understands "pi", and A will be a new list. Now ask for the fit with "R ~b*0.24/A" and it will fit the data and return a slope. The slope is the resistivity.

A)7.3 x 10-11

b)1.1x10-4

c)1.7 x 10-8

d)7.3 x 10-8