Write a C++ program using a while loop to calculate the value of /2 accurate to 6 digits after the decimal point using the following series: /2=1+1/3+(12)/(35)+(123)/(357)+ Display the following and turn in printouts of the program and the results. The number of terms needed to find /2 The value of /2 using acos(-1)/2 using 10 digits after the decimal point. The value of /2 found with the series using 10 digits after the decimal point (the first 6 digits after the decimal point should match the value above).