Write a function i_to_a that converts a 32-bit integer into a string of ASCII digits. The function will receive as an argument a 32-bit integer and it should return a string of digits contained in the integer. The output string should be an ASCIIZ string, i.e., ends with the null character (ASCII code 0). You may assume that the input will not be a negative number or a non-decimal value or too large a number. For example, i_to_a called with the argument 12345 will return the string "12345". Write a C program (ex2. c), where main () repeatedly reads an integer from the input, then calls i_to_a () with this integer as an argument. The function i_to_a () returns a string, which main prints using printf("%s ", . . .). The program should terminate when the integer read is 0. The name and type declaration of the function you create must be: void i_to_a (char *str, int num, int base) You may assume that the input string will not be longer than 20 digits. As you can guess, the base you will be using is 10. So the function will look like void i_to_a (char *str, int num, 10). You are free to eliminate the last argument in the function too, by hardcoding it to base 10. You cannot use itoa () function that is part of the C library. You must write your own function! For printing the value read you should use printf("%d ",...).