Write a program that accepts two command line arguments. The first is the name of a file that is to be used as the input file and the second is the name of the output file. The program is to base-64 encode the first file, which is to be treated as a binary file, into the second. The first line of the output file, which is a text file, should contain the name of the first file (so that the reconstructed data can be placed in a file of the correct name later). Your program should print to the console the total number of bytes contained in the input file.

i am trying to read 062434752 from a file which from the program gives yjnq and then print that to another file.

#include #include #include

char map(unsigned value) { if (value < 26) return 'A' + value; if (value < 52) return 'a' + value - 26; if (value < 62) return '0' + value - 52; if (62 == value) return '+'; if (63 == value) return '/'; return '?'; }

unsigned unmap(char c) { if ('/' == c) return 63; if ('+' == c) return 62; if (isdigit(c)) return 52 + (c - '0'); if (islower(c)) return 26 + (c - 'a'); if (isupper(c)) return 0 + (c - 'A'); return 0xFFFFFFFF; }

int main(void) { char *message = "Hello World!"; unsigned data = 062434752; // 0xCA35EA; char chars[4]; printf("DATA: %o ", data); for (int i = 0; i < 4; i++) { unsigned value = (data >> (18 - 6 * i)) & 077; chars[i] = map(value); } printf("MSG : "); for (int i = 0; i < 4; i++) { printf("%c", chars[i]); } printf(" "); data = 0; for (int i = 0; i < 4; i++) { unsigned value = unmap(chars[i]); data <<= 6; data += value; } printf("DATA: %o ", data);

return EXIT_SUCCESS; }