Write an assembly program to read three 32-bit signed integers from the user.?

A BCD number is meant to conveniently represent decimal numbers in a way that is easier for humans to interpret. Each 4-bit number represents a unique decimal digit. For example:

8 7 6 2 in BCD would be represented at 1000 0111 0110 0010

However, the underlying binary bit pattern (1000011101100010) is actually 34,658 in decimal.

Write an assembly program to read a four character BCD number from the user. This will be read in as a standard integer. However, you are to convert this number to its BCD equivalent, and print out this decimal number. You can assume that the input is always 4 characters and is legal (i.e. only the digits from 0-9 will appear).

Heres an example:

User types in 8762. This is stored in the computer as 100010001110102

We need to convert it to the representation 1000 0111 0110 0010, which is BCD for 8762 (Notice the first 4 bits has an 8, the next 4 bits has a 7, and so on)

Print out that BCD value (10000111011000102) as a decimal: 34658 (Your syscall print_int does this anyway).

**OUTPUT SHOULD READ**

BCD: 8762 Binary: 34658