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Write down the iterated integral which expresses the surface area of z = y' cos' a over the triangle with vertices (-1, 1), (1, 1),

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Write down the iterated integral which expresses the surface area of z = y' cos' a over the triangle with vertices (-1, 1), (1, 1), (0, 2): h(x, y) dxdy 1 2 f(y) = V - 2 g(y) = 2-y h(x, y) = V 1+ (-5y cos x sin x ) + (32 cos5x)2

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