x = 1+ 2t x = 2+ 3s 8. In three-space, find the intersection point of the two lines: y = -3 + t & y =-1 + 2s Z =-3 Z = S a) (1, -3, -3) b) (2, 1, -3) c) (2, -1,0) d) (-7, -7,-3)