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x + 1 de You should rewrite the integral as to help identify u. (a) Let u = /2 + 1 (b) Then du

x + 1 de You should rewrite the integral as to help identify u. (a) Let u = /2 + 1 (b) Then du = 3 / dx or (c) Now substitute 213 [2/ 1/23/2+1 dr du = x/2 dx

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