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x 4 x + - 8. If the sum of the maximum and minimum value of y = log2 (x* + x +1) - log2
x 4 x + - 8. If the sum of the maximum and minimum value of y = log2 (x* + x +1) - log2 (x* + x +2x + x +1) can be expressed in the form of ((log, m)-n), where mand n are relatively prime positive integers then the value of (m+n) is A) 5 B) 2 C) 3 D) 4 m
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