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X is x*(py) > x*(py) > x*(y) If this is the case then why is B(x*(py))-x*(py)y > B(x*(py))-x*(py)y Since the first equation that has is
X is x*(py) > x*(py) > x*(y)
If this is the case then why is
B(x*(py))-x*(py)y > B(x*(py))-x*(py)y
Since the first equation that has is smaller but in second equation with the is smaller.
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