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x y 1 6 2 15 3 22 4 23 5 29 6 29 7 31 8 32 9 34 possibly by subbing values in
x y 1 6 2 15 3 22 4 23 5 29 6 29 7 31 8 32 9 34
x | y |
1 | 6 |
2 | 15 |
3 | 22 |
4 | 23 |
5 | 29 |
6 | 29 |
7 | 31 |
8 | 32 |
9 | 34 |
possibly by subbing values in to find intercepts, needed is a log function in the form y=alogx+d for the above given set of data
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