X1 = 80.9 X =91.3 51 = 1.20 $2 = 2.50 SEMI - .38 SEM, = .79 Degrees of freedom at .05 (df) = 18 t ratio =-11.95 t value = 2.101 Determine If there is a significant difference in the group means of the test. With the level of significance at .0S retain or reject the null hypothesis: The null hypothesis is rejected, you may conclude that running 5 days a week develops cardiorespiratory endurance better than running 3 days a week (20 pts.).Name: EXAMPLE FINAL PROJECT KES 5314: Diagnostic Test and Measurements Population: All freshmen students at Sul Ross (5 pts.) Sample: We randomly selected 20 freshmen students from Sul Ross (10 in each group) and tested their cardiorespiratory fitness using the Harvard step Test (5 pts.). An Independent variable is the treatment in the study. In our case it was running 3 days or 5 days a week. The dependent variable is the variable that researchers observe to see if it changes as a result of the treatment in the study. The results of the step test administered to each group after running is our dependent variable (10 pts.). Inferential statistics: We are trying to reach a conclusion that extends beyond the immediate data alone. We will use a sample of 16 students (10 for each group) from our physical education program at Sul Ross. We will Infer from the samples using the t-Test for Independent Groups that there will not be a significant difference in cardiorespiratory fitness from running three days a week and running five days a week (10 pts.). Null hypothesis: There will be no significant difference between the means of the group running 3 days a week and the means of the group running 5 days a week (10 pts.)- Table with a title and tabulations of results (40 pts.]. t-Test for Independent Groups: Harvard Step Test Group Running 3 Days/Week Group Running 5 Days/Week X1 X,2 640D 88 7744 79 6241 92 8464 81 6561 93 8649 80 6400 95 9025 82 6724 91 8281 81 6561 89 7921 80 6400 88 7744 82 6724 90 8100 81 6561 94 8836 83 6889 8649 X: = 809 X1 = 65461 X1 = 913 X1 = 83413